Answer :
The z-score of the number of teens that transfered schools is the standard score
The obtained value of z is 5
How to determine the value of z?
The given parameters are:
- Population mean, μ = 50
- Population standard deviation, σ = 10
- Sample, x = 100
- Sample mean = 59
The z-value is calculated using:
z = (x - μ)/σ
Substitute known values in the above formula
z = (100 - 50)/10
Evaluate the difference
z = 50/10
Evaluate the quotient
z = 5
Hence, the obtained value of z is 5
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