Answer:
y ≥ -x - 4
Step-by-step explanation:
[tex]\sf let (x_1,y_1)=(-4,0)\\\\let (x_2,y_2)=(0,-4)[/tex]
[tex]\sf slope \ (m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-0}{0-(-4)}=-1[/tex]
Slope-point form of linear equation:
[tex]\sf \implies y-y_1=m(x-x_1)[/tex]
[tex]\sf \implies y-0=-1(x-(-4))[/tex]
[tex]\sf \implies y=-x-4[/tex]
For ≤ or ≥ graph a solid line
For < or > graph a dashed line
For shading above the line: y ≥ or y >
For shading below the line: y ≤ or y <
Therefore, as the line is solid and shading is above the line:
[tex]\sf y\geq -x-4[/tex]
