Using the vertical asymptote of the function, it is found that it is given by:
[tex]f(x) = -1.5\frac{(x - 4)}{x - 2}[/tex]
What are the asymptotes of a function f(x)?
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the x-intercept of the graph is x=4, hence the numerator is a(x - 4).
The graph has one vertical asymptote at x=2, hence the denominator is x - 2.
Hence:
[tex]f(x) = \frac{a(x - 4)}{x - 2}[/tex]
The y-intercept of the graph is y=−3, hence:
[tex]-3 = \frac{a(0 - 4)}{0 - 2}[/tex]
[tex]-4a = 6[/tex]
[tex]a = -1.5[/tex]
Thus, the function is:
[tex]f(x) = -1.5\frac{(x - 4)}{x - 2}[/tex]
More can be learned about asymptotes at https://brainly.com/question/16948935
