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Given that the molar mass of naoh is 40.00 g/mol, what mass of naoh is needed to make 2.500 l of a 2.000 m naoh solution? use molarity equals startfraction moles of solute over liters of solution endfraction.. 0.1250 g 5.000 g 32.00 g 200.0 g

Answer :

The mass of Sodium hydroxide which is needed to make 2.500 L of a 2.000 M NaOH solution is 200 grams.

How do we calculate mass from moles?

Mass of any substance will be calculated by using their moles as:

n = W/M, where

W = required mass

M = molar mass

Given that, molarity of NaOH = 2M

Volume of NaOH solution = 2.5L

Moles of NaOH will be calculated by using the below equation as:

M = n/V

n = (2)(2.5) = 5 moles

Now we calculate the mass of NaOH of 5 moles as:

W = (5mol)(40g/mol) = 200g

Hence option (4) is correct.

To know more about moles, visit the below link:

https://brainly.com/question/15303663

Answer:

d

Explanation:

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