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A comparison between species: Biologists wish to compare the prevalence of a genetic mutation across
two species of Neema Toads. In a sample of 9 Neema Toads of Species I, 0.6% had the mutation while in a
sample of 12 Neema Toads of Species II, 1% showed the mutation. Is there significant evidence to suggest a
difference in the prevalence of the mutation across the two species? Conduct a hypothesis test at a
significance level of a = 0.01.

Answer :

Ogorwynego

The result from the hypotheis test below shows that there is no significant evidence existing to show difference in the mutation.

How to solve for the z statistics

The hypothesis for this test has been stated below:

H0: pI - pII = 0

Ha: pI - pII ≠ 0

n1 = 9

p1 = 0.6%

n2 = 12

p2 = 1%

Using the z statistics formula

[tex]\frac{0.006-0.01}{\sqrt{0.000663+0.000825} } \\\\\frac{-0.004}{\sqrt{0.001488} }[/tex]

z = -0.103

p value = z(-0.103) = 0.4589

The pvalue is greater that 0.01

The decision is to fail to reject the null hypothesis.

There is no significant evidence to show that there is a difference in the prevalence of mutation.

Read more on hypothesis testing here: https://brainly.com/question/15980493

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