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Answer :

Charliethebest2002go

Answer:

  • [tex]\boxed{\sf{4}}[/tex]

Step-by-step explanation:

Use the order of operations to solve this problem.

[tex]\Longrightarrow: \sf{\sqrt{28-3(4)} }[/tex]

Remove parentheses.

→ (4)=4

Rewrite the problem down.

[tex]\Longrightarrow:\sf{\sqrt{28-3*4} }[/tex]

PEMDAS stands for:

  • Parentheses
  • Exponents
  • Multiply
  • Divide
  • Add
  • Subtract

→ 28-3*4

Multiply.

→ 3*4=12

→ 28-12

Subtract.

→ 28-12=16

[tex]\Longrightarrow:\sf{\sqrt{16} }[/tex]

[tex]\Longrightarrow\sf{\sqrt{16}=4^2 }[/tex]

Use the radical rule.

[tex]\Longrightarrow: \sf{4^2=\boxed{\sf{4}}[/tex]

  • Therefore, the correct answer is 4.

I hope this helps you! Let me know if my answer is wrong or not.

Answer:

[tex]\±4[/tex]

Step-by-step explanation:

Given expression: [tex]\sqrt{28 - 3(4)}[/tex]

Here, we can see that the terms, 28 and 3(4) are inside the root. Since the two terms are inside the root, we can subtract them. Therefore:

  • [tex]\implies\sqrt{28 - 3(4)}[/tex]
  • [tex]\implies\sqrt{28 - 12}[/tex]
  • [tex]\implies\sqrt{16}[/tex]

Usually, [tex]\sqrt{16}[/tex] can also be written as [tex]\sqrt[2]{16}[/tex]. Therefore:

  • [tex]\implies\sqrt[2]{16} = \sqrt[2]{4 \times 4} = \± 4[/tex]

Therefore, the simplified expression is ±4.

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