Answer:
2) 4,2
Step-by-step explanation:
Factor by grouping:
[tex]x^2-6x+8\\\\x^2-4x-2x+8\\\\x(x-4)-2(x-4)\\\\(x-2)(x-4)[/tex]
Setting the expression equal to 0 and using the Zero Product Property, [tex]x=2[/tex] and [tex]x=4[/tex], which are the factors of the original polynomial.
