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Answer :

Loneguygo

[tex]\text{Given that, c=3, d=6}\\\\\dfrac{4d}{c+3} = \dfrac{4(6)}{3+3} = \dfrac{4(6)}6 = 4[/tex]
What I got:

11

Explanation:

4d / c+3

4 x 6 = 24

24 / 3 + 3

24/3 = 8

8+3= 11

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