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1. How many moles of oxygen will occupy a volume of 2. 5 liters at 1. 2 atm and 25ºC?

2. What volume will 2. 0 moles of nitrogen occupy at 720 mm Hg and 20. 0ºC?

3. What pressure will be exerted by 25 g of CO2 at a temperature of 35ºC and a volume of 500. 0 mL?

4. At what Celcius temperature will 5. 00 g of Cl2 exert a pressure of 900. 0 mm Hg at a volume of 750 mL?

Answer :

Onyebuchinnajigo

(1) The number of moles of oxygen gas is 0.123 mole.

(2) The volume occupied by the nitrogen gas is 50.75 Liters.

(3) The pressure exerted by the CO2 gas is 28.7 atm

(4) The temperature of the Cl2 gas is -118.37⁰C

Number of moles of oxygen

The number of moles of oxygen occupied at the given condition is calculated as follows;

PV = nRT

n = PV/RT

where;

  • T = 25ºC = 273 + 25 = 298K
  • R is ideal gas constant = 0.08205 L.atm/mol.K

n = (2.5 x 1.2) / (0.08205 x 298)

n = 0.123 mol

Volume of the gas

PV = nRT

V = nRT/P

where;

  • R = 62.36 L.mmHg/mol.K

V = (2 x 62.36 x 293) / (720)

V = 50.75 Liters

Pressure of the gas

PV = nRT

P = nRT/V

where;

  • n is number of moles

Molar mass of CO2 = 44

n = 25/44 = 0.568

P = (0.568 x 0.08205 x 308)/(0.5)

P = 28.7 atm

Temperature of the gas

T = PV/nR

molar mass of Cl2 = 71 g

n = 5/71 = 0.07

T = (900 x 0.75)/(0.07 x 62.36)

T = 154.63 K

T = 154.63 - 273 = -118.37⁰C

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