Answer :
[tex]\text{For arithmetic series, the common difference will be same. }\\\\~~~~~~(2k-1)-(k+11) = (2k+7)-(2k-1)\\\\\implies 2k-1-k-11 = 2k+7-2k+1\\\\\implies k-12=8\\\\\implies k=8+12\\\\\implies k=20[/tex]
[tex]\text{For arithmetic series, the common difference will be same. }\\\\~~~~~~(2k-1)-(k+11) = (2k+7)-(2k-1)\\\\\implies 2k-1-k-11 = 2k+7-2k+1\\\\\implies k-12=8\\\\\implies k=8+12\\\\\implies k=20[/tex]