By evaluating, we will see that for x = 7 h(x) exceeds g(x).
For which value of x does h(x) first exceed g(x)?
We have:
h(x) = 2*(2)^x
g(x) = 22x - 4
Now we can evaluate both function in the different options:
h(5) = 2*(2)^5 = 64
g(5) = 22*5 - 4 = 106
We can see that for x = 5, h(x) does not exceed g(x), let's try the next one.
h(6) = 2*(2)^6 = 128
g(6) = 22*6 - 4 = 128
So, for x = 6 both functions have the same output, then for x = 7 we will see that h(x) exceeds g(x).
The correct option is B.
If you want to learn more about functions:
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