The function h(x) = 6x² - 60x + 147 is a quadratic function, and the axis of symmetry of the function is x = 5
How to determine the axis of symmetry?
The equation of the function is given as:
h(x) = 6x² - 60x + 147
Differentiate the function
h'(x) = 12x - 60
Set the function to 0
12x - 60 = 0
Add 60 to both sides
12x = 60
Divide both sides by 12
x = 5
Hence, the axis of symmetry of the function is x = 5
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