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Mathematics

Answered

If 3x^2+3y^2 = 42 and xy = -15, find the value of (x-y)^2

Answer :

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Answer:

3x² + 3y² = 42

3 ( x² + y² ) = 42

x² + y² = 14

xy = -15 ( given )

(x-y)² = x² + y² - xy

14 - ( -15 )

14 + 15

29

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