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Jake is planning a trip to china. he has made a list of cities he would like to visit, as well as the approximate amount of money he plans to spend in each as a result of travel, lodging, shopping, and so on. all costs are listed in renminbi (¥). city cost (¥) tianjin 557 nanjing 681 zhengzhou 595 beijing 728 wuhan 449 chengdu 534 unfortunately, jake only has ¥2,920 available. what is the cheapest city that jake can remove from his travel plans and still stay under budget? a. tianjin b. wuhan c. nanjing d. beijing

Answer :

The cheapest city that Jake can remove from his travel plans and still stay under his budget is Nanjing.

What is the cheapest city that can be removed?

A budget is a plan of expected expenditures.

Total cost of the cities = 557 + 681 + 595 + 728 + 449 + 534 = 3544

Total cost of the cities if Nanjing is removed = 3544 - 681 = $2863

To learn more about subtraction,please check: https://brainly.com/question/915789

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