The vertex form of the given quadratic equation is:
[tex]y = 6*(x + 1)^2 - 16[/tex]
We have the quadratic equation:
[tex]y = 6x^2 + 12x -10[/tex]
First, we need to find the vertex. The x-value of the vertex is:
h = -12/2*6 = -1
To get the y-value of the vertex, we need to evaluate the function in h, so we get:
y = 6 - 12 - 10 = -16
Then the vertex is (-1, -16)
This means that the vertex form is:
[tex]y = 6*(x + 1)^2 - 16[/tex]
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Answer:
y = 6(x + 1)2 – 16. D ON EDGE
Step-by-step explanation:
