Answer :
Taking into account the definition of molarity, 4.08 grams of ammonium sulfide are present in 3.00 L of a 0.0200 M solution.
Definition of molarity
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]Molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Mass of ammonium sulfide
In this case, you know:
- Molarity: 0.0200 M
- number of moles: ?
- volume: 3 L
Replacing in the definition of molarity:
[tex]0.0200 \frac{moles}{liter}=\frac{number of moles}{3 L}[/tex]
Solving:
0.0200 [tex]\frac{moles}{liter}[/tex]× 3 L= number of moles
0.06 moles= number of moles
On the other side, the molar mass is the amount of mass that a substance contains in one mole. In this case, the molar mass of ammonium sulfide is 68 g/mole.
Then, the amount of mass contained in 0.06 moles is calculated as:
0.06 moles×[tex]\frac{68 grams}{1 mole}[/tex]= 4.08 grams
Finally, 4.08 grams of ammonium sulfide are present in 3.00 L of a 0.0200 M solution.
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