given:
[tex]10 ^{2y} = 25[/tex]
to find:
[tex] {10}^{y} = .......[/tex]
solution:
[tex]10 ^{2y} = 25[/tex]
[tex] (10y {)}^{2} = {5}^{2} [/tex]
[tex]10y = 5[/tex]
[tex] \frac{1}{ {10}^{y} } = \frac{1}{5} [/tex]
[tex] {10}^{ - y} = \frac{1}{5} [/tex]
therefore, the correct answer is option E.
