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A submarine is moving toward another submarine at 9.20 m/s. It emits a 3.50-MHz ultrasound. What frequency would the second sub, at rest, detect? The speed of sound in water is 1482 m/s.

Answer :

Answer:

For a moving source and stationary object-

f' = f (V / V - vs)

f' = 3.50 Mhz * (1482 / (1482 - 9.2)) = 3.52 Mhz

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