Solution:
[tex](x+3)^2+(y-4)^2+16[/tex]
The center of the circle is at: [tex]C=(-3,4)[/tex]
The radius of the circle is [tex]r=4[/tex].
explanation:
A circle with center at [tex](h,k)[/tex] and a radius of [tex]r[/tex] has equation [tex](x-h)[/tex]
In this example our circle equation can be written as:
[tex](x-(-3))^2+(y-4)^2=(4)^2[/tex]
So, we have: [tex]h=-3,k=4[/tex] and [tex]r=4[/tex]
Learn more about finding the center and the radius of a circle here:
brainly.com/question/11779639
