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Answer :

Eduard22slygo

Given that the linear expansion of the pipe is 12×10¯⁶ K¯¹, the pipe extends by 0.024 mm

Data obtained from the question

  • Original length (L₁) = 100 mm
  • Change in temperature (ΔT) = 20 K
  • Coefficient of expansion (α) = 12×10¯⁶ K¯¹
  • Change in length (ΔL) =?

How to determine the new diameter

α = ΔL / L₁ΔT

12×10¯⁶ = ΔL / (100 × 20)

12×10¯⁶ = ΔL / 2000

Cross multiply

ΔL = 12×10¯⁶ × 2000

ΔL = 0.024 mm

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