The representation of the vector in trigonometry form is t = 13 ❬cos 112.62°, sin 112.62°❭
The representation of complex number in polar form is expressed as;
y = r(cosФ + isinФ)
where;
r is the modulus
Ф is the argument
Given the vector t = –5i + 12j, the modulus of the vector is given as;
r = √(-5)²+(12)²
r = √25 + 144
r = √169
r = 13
Determine the angle between the vectors
Ф = arctan(-12/5)
Ф = -67.38
Since tan is negative in the second quadrant, hence;
Ф = 180 - 67.38
Ф = 112.62°
The representation of the vector in trigonometry form is t = 13 ❬cos 112.62°, sin 112.62°❭
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