The equation of the function is y = sec(2(x + π/6)) + 2
How to determine the equation of the function?
From the graph, we have the following parameters:
- Local maximum = 3
- Local minimum = 1
- Period = 2
- Phase shift = π/6
A secant function is represented as:
y = A sec(b(x + c)) + d
Where:
A = 0.5 * (max - min) = 0.5 * (3 - 1) = 1
b = Period = 2
c = Phase shift = π/6
d = 0.5 * (max + min) = 0.5 * (3 + 1) = 2
So, we have:
y = 1 * sec(2(x + π/6)) + 2
Evaluate
y = sec(2(x + π/6)) + 2
Hence, the equation of the function is y = sec(2(x + π/6)) + 2
Read more about secant function at:
https://brainly.com/question/13276558
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