Answer :
Given:
- d= 94 cm
Note that:
- d= Diameter
To find:
- The radius of the circle
- The area of the circle
Solution:
[tex]\huge\boxed{Formula: r= \frac{d}{2}}[/tex]
Substitute the values according to the formula.
[tex]r=\frac{94}{2}[/tex]
[tex]\large\boxed{r=47 \: cm}[/tex]
Now, let's find the area.
[tex]\huge\boxed{Formula:a= \pi{r}^{2}}[/tex]
So, we'll have to multiply π, 47 and 47.
Substitute the values according to the formula.
[tex]a= \pi{47}^{2}[/tex]
[tex]a= 6939.778172 \: {cm}^{2}[/tex]
[tex]\large\boxed{a= 6939.8 \: {cm}^{2}(1 \: d.p)}[/tex]
Hence, the area of the given circle is 6939.8 square centimeters.
Hi student, let me help you out! :)
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We are asked to find the radius & area of the circle.
To find the [tex]\star\bf{radius}\star[/tex], we divide the diameter by 2:
[tex]\star~\bf{94\div2}[/tex]
[tex]\star~\bf{Radius=47}\star[/tex]
Now that we have the radius, let's compute the area! :)
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Calculating the Area
We can work out the area of a circle by using this formula:
[tex]\star\boxed{\pmb{A_{(circle)}=\pi r^2}}\star[/tex]
Where
[tex]\dag[/tex] A=Area of a circle
[tex]\dag[/tex] [tex]\pi =3.14...[/tex]
[tex]\dag[/tex] r=radius
Have you noticed the [tex]\large\pmb{^2}[/tex] next to r? This tells us that we should multiply the radius times itself.
Now it's time to substitute the values:
[tex]\star~\large\pmb{A=3.14\times47^{2}}\star[/tex]
Let's simplify it. The acronym PEMDAS will help us, and we won't make any mistakes in the Order of Operations! :)
Here's what it stands for:
P=Parentheses
E=Exponents
M=Multiplication
D=Division
A=Addition
S=Subtraction
2 is an exponent.
So what do you think we should do first?
[tex]\square[/tex] Square 47.
[tex]\square[/tex] Multiply 3.14 times 47 and then square.
That's right, we should square 47 first. :)
[tex]\star~\large\pmb{A=\pi \times2209}}\star[/tex]
Now, according to PEMDAS, we should multiply pi times 2209; after multiplying, we obtain:
[tex]\star~\large\pmb{A=6936.8\:cm^2}\star[/tex]
Remember, the area of any shape is measured in units squared.
[tex]\ddot\bigstar[/tex] Remember this...
[tex]\fbox{\bf{The\;area\;of\;any\;shape\;is\;measured\;in\;units\;squared}}[/tex]
Hope this helps you out! :D
Ask in comments if any queries arise.
#StudyWithBrainly
~Just a smiley person helping fellow students :)
[tex]\bigstar\footnotesize\pmb{M^ar_ib^el\;Peri}[/tex]