Step-by-step explanation:
here ,
[tex]cosec \alpha = \frac{1}{ \sin( \alpha ) } [/tex]
now,
cosec(2-45°)=2
or,
1/sin(2-45°) =2
or,
1/sin2cos45°-cos2sin45=2
or,
[tex] \frac{1}{ \sin(2) \frac{1}{2} - \cos(2) \frac{1}{2} } = 2[/tex]
or,
sorry I have that much qualifications to work on this question and hoping this much will make bit easy for you to solve it further
