Answer :
The direction of the force is given as = 38.21⁰ while the magnitude is given as 7N
The magnitude of the resultant force is given as
Fr = [tex]\sqrt{F1^2+F2^2+2F1F2CosO}[/tex]
∅ = 60 degrees
= √3² + 5² + 2*3*5cos60
= √49
FR = 7N
How to solve for the direction of the force
7cos∅ = 3 + 5cos∅
7cos ∅ = 3 + 2.5
cos∅ = 5.5/7
∅ = cos⁻¹0.7857
= 38.21⁰
Hence the direction of the force is = 38.21⁰
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