Answer :
Answer: 13.9
Explanation:
LiOH is a base, so the pOH is given by [tex]-\log(0.8)=0.0969[/tex].
So, since pOH + pH = 14, the pH is 14-0.0969, which is about 13.9
Answer: 13.9
Explanation:
LiOH is a base, so the pOH is given by [tex]-\log(0.8)=0.0969[/tex].
So, since pOH + pH = 14, the pH is 14-0.0969, which is about 13.9