Based on the calculations, the speed of this roller coaster at the bottom of the hill is equal to: B. 39.6 m/s.
Given the following data:
Height = 80.0 meters.
Scientific data:
Acceleration due to gravity (g) = 9.8 m/s².
In accordance with the law of conservation of energy, the potential energy possessed by the roller coaster at the top is equal to the kinetic energy possessed by the roller coaster at the bottom of the hill:
PE = KE
mgh = ½mv²
2mgh = mv²
v = √(2gh)
Substituting the given parameters into the formula, we have;
v = √(2 × 9.8 × 80)
v = √1,568
Speed, v = 39.6 m/s.
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