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Answer :

SomeoneInNeedOfHelp2go

Answer:

To be clear, do u want the angle of M?

Answer:

secM = [tex]\frac{17}{15}[/tex]

Step-by-step explanation:

secM = [tex]\frac{1}{cosM}[/tex]

cosM = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{MN}{LM}[/tex] = [tex]\frac{15}{17}[/tex] , then

secM = [tex]\frac{1}{\frac{15}{17} }[/tex] = [tex]\frac{17}{15}[/tex]

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