The distance between the two points. (-1, 6). (2.8) is 3.61 units
The points are given as: (-1,6) and (2,8)
The distance is calculated using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}[/tex]
This gives
[tex]d = \sqrt{(-1 -2)^2 + (6 -8)^2}[/tex]
Evaluate the sum of squares
[tex]d = \sqrt{13}[/tex]
Evaluate the exponent
d = 3.61
Hence, the distance between the two points. (-1, 6). (2.8) is 3.61 units
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