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If 19.4 mL of a Ca(OH)₂ solution are needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution, what is the concentration (molarity) of the
Ca(OH)₂ solution?
Select one:
O a. 0.009 M
O b. 1.6 M
OC 0.08 M
O d. 0.1 M

Answer :

Samueladesida43go

The concentration (molarity) of the Ca(OH)₂ solution needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution is 0.162M (option D).

How to calculate molarity?

The molarity of a solution can be calculated using the following formula:

CaVa = CbVb

Where;

  • Ca = concentration of acid
  • Cb = concentration of base
  • Va = volume of acid
  • Vb = volume of base

31.5 × 0.1 = 19.4 × Cb

3.15 = 19.4Cb

Cb = 0.162M

Therefore, the concentration (molarity) of the Ca(OH)₂ solution needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution is 0.162M.

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