👤

Answer :

Anthamhgo

Answer:

7.21

Step-by-step explanation:

There is a formula to find the area of a side of a rhombus given 2 diagonals.

It is:  [tex]\frac{\sqrt{p^{2}+q^{2} } }{2}[/tex]

64 + 144 = 208

[tex]\sqrt{208}[/tex] = 14.42

14.42 / 2 =

7.21
The diagonals of the rhombus meet perpendicularly, so you have four right triangles. Because of this you can use the Pythagorean theorem with 8 and 12 to find the side.

Theorem: a^2 + b^2 = c^2

8^2 + 12^2 = c^2
64+144 = c^2
c^2 = 208
c = sqrt208

Go Teaching: Other Questions