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When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 35 cm . What is the second student's mass

Answer :

Answer:

The mass of the second student is 60 kg.

Explanation:

Note: It is assumed that radius of piston is 0.23 m and density ρ is 850 kg/m^3 and mass of first student is 55 kg.

There occurs a change in pressure on a piston when some mass is added on the other piston.

This change of mass on the piston is given by the formula,

Δm=ρhA/g

where A is the area of piston.

Given h=35 cm or 0.35 m, change in mass is,

Δm=850*(0.35)*π*(0.23)^2 / 9.8

Δm=5.0 kg

Therefore, the mass of the second student is 55+5=60 Kg

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