The equation of the line is y = -11x + 232
How to determine the equation?
The given parameters are:
Slope (m)= -11
Point (x1, y1) = (31, -109)
The linear equation is then calculated as:
y = m(x - x1) + y1
This gives
y = -11(x - 31) - 109
Evaluate the product
y = -11x + 341 - 109
Evaluate the like terms
y = -11x + 232
Hence, the equation of the line is y = -11x + 232
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