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Answer :

So Explicit formula for 2nd one

  • 2a_{a-1}

Or general formula as per Geometric progression

  • a_n=ar^{n-1}=1(2)^{n-1}

For 50 years there are 365(50)=18250days excluding leap years (We will check for leap year if neck to neck situation arises)

Now find sum

Sum of 18250 terms

[tex]\\ \rm\Rrightarrow \dfrac{a(r^n-1)}{r-1}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1(2^{18250}-1)}{2-1}[/tex]

1 from both denominator and numerator cancels out

[tex]\\ \rm\Rrightarrow 2^{18250}-1[/tex]

[tex]\\ \rm\Rrightarrow 6.272214002E5493[/tex](Accurate)

It's far more than 1 M so second option would give you more penny

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