Answer :
The probability that 3 separate flights will all take place is 0.531441
let A = event of scheduled flight actually take place
According to the question, P(A)=0.81
Given that 3 separate flights will all take place is an independent event.
Hence, we can use the multiplicative rule which says If the probability that one given flight takes place is 0.81 then the probability of 3 flights taking place is:
P(A∩B∩C) = P(A)*P(B)*P(C)
= 0.81*0.81*0.81
= 0.531441
so, the Probability that 3 separate flights will take place is 0.531441
The formula used for independent events:
P(A∩B∩C) = P(A)*P(B)*P(C)
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