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13. Use mole ratios to identify the limiting reagent in the following reaction: 3.10 mol of sodium mixes with 4.17 mol of water to form sodium hydroxide and hydrogen gas.


14. Determine the number of excess moles of the excess reagent in the following reaction: 4.80 mol of calcium mixing with 3.55 mol of oxygen gas, making calcium oxide.

Answer :

Osenigo

13) The limiting reagent is water.

14) Oxyge is in excess by 1.15 mol

Limiting reagent

13) According to the equation of the reaction:

[tex]2Na + 2H_2O --- > 2NaOH + H_2[/tex]

The mole ratio of the reactants is 1:1.

But 3.10 mol of sodium and 4.17 mol of water were reacted. Thus, water is in excess while sodium is limiting.

14) [tex]2Ca + O_2 --- > 2CaO[/tex]

Mole ratio of reactants = 2:1

4.80 mol Ca and 3.55 mol oxygen were reacted. Thus, oxygen is in excess.

Excess oxygen = 3.55 - 4.80/2 = 1.15 mol

More on limiting reagents can be found here: https://brainly.com/question/11848702

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