A charge of 5.4 C experiences a force of 25.0 in an electric field. What is the strength of electric field at that point ? If the 5.4 C is replaced by a charge of half the magnitude, 2.7 C, how much force would this charge experience at that point ? Remember to identity all of your data, write the equation, and show your work. (5 points)

The strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.

What is the electric field strength?

The electric field strength is defined as the ratio of electric force to charge.

Given data;

q₁ = 5.4 C

F₁ is the electric force in case1

E is the electric field =?

F₂ is the electric force in case 2

q₂ is the charge 2

The strength of the electric field at that point is;

F₁=Eq₁

E₁=F/q₁

E₁=25.0 N / 5.4 C

E₁=4.587 N/C

The force would this charge experience at that point when the charge is 2.7 C;

F₂=Eq₂

F₂=4.587 N/C × 2.7 C

F₂ = 12.38 N

Hence the strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.

To learn more about the electric field strength, refer to the link;

https://brainly.com/question/4264413

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