A rectangle has a perimeter of 92cm and its length is 1cm more than twice its width.

Using the definition of perimeter write an equation for P in terms of L and W
Using the relationship given in the problem statement, write an equation for L in terms of W.

This question does not ask you to compute L and W but if you wanted to do that use the following steps
Substitute for L from equation 2 to equation 1 giving
P = 2(2W+1) + 2W = 4W + 2 + 2W = 6W + 2

We know P = 92

So 6W + 2 = 92
Subtracting 2 from both sides we get 6W = 90
Dividing both sides by 6 gives us W = 15
and L = 2 * 15 + 1 = 31

We can check this by finding the perimeter from L and W
perimeter = 2(L+W) = 2(31 + 15) = 2 (46) = 92 which matches the data in the question

A rectangle has a perimeter of 92cm and its length is 1cm more than twice its width. Using the definition of perimeter write an equation for P in terms of L and W Using the relationship given in the problem statement, write an equation for L in terms of W.

Answer :

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A rectangle has a perimeter of 92cm and its length is 1cm more than twice its width.

Using the definition of perimeter write an equation for P in terms of L and W
Using the relationship given in the problem statement, write an equation for L in terms of W.