The volume of the aqueous solution of sodium sulfate required is 153.85 mL.
The number of moles of the salt in the given mass is calculated as follows;
moles = reacting mass / molar mass
molar mass of sodium sulfate = 142 g/mole
moles = (4.27) / (142)
moles = 0.03 mole
Concentration = moles/volume in liters
0.195 = 0.03/V
V = 0.03/0.195
V = 0.15385 liters
V = 153.85 mL
Thus, the volume of the aqueous solution of sodium sulfate required is 153.85 mL.
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