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Consider the parametric equations below.
x = t^2 − 3, y = t + 2, −3 ≤ t ≤ 3
Eliminate the parameter to find a Cartesian equation of the curve.
for
−1 ≤ y ≤ 5

Answer :

LammettHashgo

Solve the second equation for [tex]t[/tex], then substitute it into the first equation.

[tex]y = t + 2 \implies t = y-2[/tex]

[tex]x = t^2 - 3 \implies \boxed{x = (y-2)^2 - 3}[/tex]

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