Answer: [tex]\Large\boxed{0.84~J/g^\circ C}[/tex]
Explanation:
Given information
[tex]Q~(Energy)=99,100~J[/tex]
[tex]m=3.47~kg[/tex]
[tex]\Delta T=(T_{Final}-T_{Initial})=(45-11)=34^\circ C[/tex]
Given formula
[tex]Q=m\times c\times\Delta T[/tex]
[tex]Q=Energy\\m=mass\\c=specific~heat\\\Delta T=Change~in~temperature[/tex]
Convert the unit of mass into Grams
[tex]1~kg=1000~g\\[/tex]
[tex]3.47~kg=3.47\times 1000=3470~g[/tex]
Substitute values into the given formula
[tex](99100)=(3470)\times c \times(34)[/tex]
Simplify by multiplication
[tex]99100=117980~c[/tex]
Divide 117980 on both sides
[tex]99100\div117980=117980~c\div117980[/tex]
[tex]\Large\boxed{c=0.84~J/g^\circ C}[/tex]
Hope this helps!! :)
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