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If the total price for two cars at a dealership is $98,000​, where one car’s price is $13,000​ less than twice the other, what is the price of the cheaper vehicle?

Answer :

Zeinabhhgo
x + y= 98,000
2x - y = 13000

3x = 111000
x= 37,000

y= 2(37,000) - 13,000 = 61,000
therefore x is the cheaper vehicle that costs 37,000$

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