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This is an impossible formula. Pretend it is real.
If you had 1 mol of Mn4(ClO4)3 how many moles of Cl would there be?
Remember that you should never include a 1 as a subscript but for the sake of clarity for this problem you may see a 1 as a subscript.
Make sure your answer includes TWO decimal places.

Answer :

Eduard22slygo

The number of mole of Cl in 1 mole of Mn₄(ClO₄)₃ is 3.00 moles

Description of Mn₄(ClO₄)₃

From the formula of the compound, Mn₄(ClO₄)₃ the following were obtained:

  • 4 moles of Mn
  • 3 moles of Cl
  • 12 moles of O

How to determine the number of mole of Cl in 1 mole of Mn₄(ClO₄)₃

From the formula, we can see that 3 moles of Cl are present.

Thus, 1 mole of Mn₄(ClO₄)₃ will contain = 1 × 3 = 3.00 moles of Cl

Therefore, we can conclude that 1 mole of Mn₄(ClO₄)₃ contains 3.00 moles of Cl

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