Answer :
The volume of hydrogen needed to react with 5.00 L of oxygen based on the mole ratio is 10.00 L.
What volume of hydrogen gas is needed to react with 5.00 L of oxygen?
The volume of hydrogen gas is needed to react with 5.00 L of oxygen is determined from the mole ratio of the reactants as shown in the equation of reaction below:
Equation of reaction: 2 H₂ + O₂ → 2 H₂O
Mole ratio of hydrogen to oxygen = 2 : 1
Moles of gases occupies equal volume
Therefore, Volume ratio of hydrogen to Oxygen = 2 : 1
Volume of hydrogen needed to react with 5.00 L of oxygen = 5.00 * 2
Volume of hydrogen needed to react with 5.00 L of oxygen = 10.00 L
In conclusion, the volume of hydrogen required is obtained from the mole ratio of hydrogen and oxygen in the reaction.
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