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From the numeric value of the formula, the tuition and fees for the school year ending in 2010 was of $26,270.
The numeric value of a function is found replacing each instance of x by the value that we want to find.
For this problem, the cost function is given by:
T(x) = 26x² + 806x + 15610.
In which x is the number of years after 2000.
Hence the cost in 2010 will be given by:
T(10) = 26(10)² + 806(10) + 15610 = $26,270.
More can be learned about the numeric value of a function at https://brainly.com/question/28262136
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