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Answer :

[tex]\begin{gathered} 4(\frac{3}{2}f+1)-7(f+5) \\ =4(\frac{3}{2}f)+4(1)-7(f)-7(+5) \\ =2(3f)+4-7f-35 \\ =6f+4-7f-35 \\ =\text{ 6f-7f+4-35 (collecting like terms)} \\ =-f-31 \end{gathered}[/tex]

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