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Answer :

[tex]c(n)=-6(\frac{-1}{3})^{n-1}[/tex][tex]\text{For 2nd term, n=2}[/tex][tex]\begin{gathered} c(2)=-6(\frac{-1}{3})^{2-1} \\ c(2)=-6\times(\frac{-1}{3}) \\ c(2)=2 \end{gathered}[/tex]

Hence, The 2nd term of the sequence is 2.

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