Answer :
[tex]Pr(E)=\frac{n(E)}{Total}[/tex][tex]\begin{gathered} 1,2,3,4,5,6,7,8,9,10 \\ n(\text{even)}=5 \\ Pr(\text{even)}=\frac{5}{10}=\frac{1}{2} \end{gathered}[/tex]
The likelihood of the event is 1/2