Answer :
Answer
128.62 g LiHCO
Explanation
Balanced chemical reaction:
LiOH + CO₂ → LiHCO₃
Molar masses
LiOH = 23.95 g/mol
CO₂ = 44.01 g/mol
LiHCO₃ = 68.0 g/mol
From the balanced chemical reaction;
1 mol LiOH → 1 mol LiHCO₃
Note: 1 mole of LiOH contains 23.95 g/mol and 1 mole of LiHCO₃ has 68.0 g/mol.
So,
23.95 g/mol LiOH → 68.0g/mol LiHCO
45.3 g LiOH → (68 x 45.3)/23.95 g = 128.62 g LiHCO
128.62 g LiHCO is