Answer :
[tex]\sin (A)=\frac{CO}{H}[/tex]
Where CO = Opposite catete = 3
H = Hypotenuse = 10
[tex]\sin (A)=\frac{3}{10}=0.3[/tex][tex]\begin{gathered} \sin ^{-1}(0.30)=A \\ \end{gathered}[/tex][tex]A=17.46\degree[/tex]